Given a binary tree, imagine yourself standing on therightside of it, return the values of the nodes you can see ordered from top to bottom.
For example:
Given the following binary tree,
1 <---
/ \
2 3 <---
\ \
5 4 <---
You should return
[1, 3, 4]
.Solution:
# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution(object):
def rightSideView(self, root):
"""
:type root: TreeNode
:rtype: List[int]
"""
if root == None:
return []
queue = collections.deque([root])
result = []
while queue:
n = len(queue)
for i in range(n):
node = queue.popleft()
if(i == n - 1):
result.append(node.val)
if node.left:
queue.append(node.left)
if node.right:
queue.append(node.right)
return result